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regroup 模板标签


示例

显示所有汽车,每个品牌一个新标题

{% regroup cars by brand as newlist %}

{% for x in newlist %}
  <h1>{{ x.grouper }}</h1>
  {% for y in x.list %}
    <p>{{ y.model }}: {{ y.year }}</p>
  {% endfor %}
{% endfor %}
运行示例 »

定义和用法

The regroup 标签返回一个根据指定值分组的新对象。

结果被划分为每个组一个 GroupedResult 对象,使得上面示例中的 newlist 对象看起来像这样

示例

{% regroup cars by brand as newlist %} 的结果

[
  GroupedResult(
    grouper='Ford',
    list=[
      {
        'brand': 'Ford',
        'model': 'Mustang',
        'year': '1964'
      },
      {
        'brand': 'Ford',
        'model': 'Bronco',
        'year': '1970'
      },
      {
        'brand': 'Ford',
        'model': 'Sierra',
        'year': '1981'
      }
    ]
  ),
  GroupedResult(
    grouper='Volvo',
    list=[
      {
        'brand': 'Volvo',
        'model': 'XC90',
        'year': '2016'
      },
      {
        'brand': 'Volvo',
        'model': 'P1800',
        'year': '1964'
      }
    ]
  )
]

注意:在重新分组之前,确保对象已正确排序,否则您最终将得到具有相同 grouper 名称的组。


语法

{% regroup object by object.property as newname %}

参数

描述
object 必需。要重新分组的列表或对象
object.property 必需。要根据其分组的属性的名称
newname 必需。返回对象的新的名称

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